Alapintegrálokra visszavezethető feladatok

\begin{displaymath}
\begin{array}{lll}
1) \frac {1}{3}x^3-6x+5\ln(x)+C &2)
\...
...}+C &9)
-\frac {1}{3}(5-2x)^{\frac {3}{2}}+C \\
\end{array}\end{displaymath}

$\displaystyle \int \frac {f'(x)}{f(x)}dx=\ln\vert f(x)\vert $

\begin{displaymath}
\begin{array}{lll}
10)\ln\vert 3+x^3\vert+C&11)\ln\vert\ln...
...^2(x)+C \\
19)\frac {3}{4}\tg^{\frac {4}{3}}(x)
\end{array}\end{displaymath}

Racionális törtfűggvények integráljai

$\displaystyle 20)\frac {3}{2}\int\frac {2x-2}{x^2-2x+10}+\frac {2}{9}\int\frac ...
...ac {3}{2}\ln\vert x^2-2x+10\vert+\frac {2}{3}\arctg(\frac {1}{3}x-\frac {1}{3})$

\begin{displaymath}
\begin{array}{ll}
21)\ln\vert 1+x\vert+2\ln\vert x-3\vert+...
...(x)+C &28)
\int(1+\tg^2(x)-1)dx=\tg(x)-x+C \\
\end{array}
\end{displaymath}

Parciális integrálás

\begin{displaymath}
\begin{array}{lll}
29)
-xe^{-x}-e^{-x}+C&30) \frac {1}{9}...
...c {1}{3}\frac {\ln\vert 1+2^{3x}\vert}{\ln(2)}+C
\end{array}
\end{displaymath}

$\displaystyle 37) (u=\frac {1}{2}(2x+2))\quad
\frac {1}{4}(2x+2)\sqrt{3-2x-x^2}+2\arsh(\frac {1}{2}+\frac {x}{2})+C$

\begin{displaymath}
\begin{array}{lll}
38)\frac {1}{4}(2x-2)\sqrt{5-2x+x^2}+2\...
...-2\sqrt{2}\ln\vert\sqrt{2}x+\sqrt{2x^2-8}\vert+C
\end{array}
\end{displaymath}

Vegyes feladatok

\begin{displaymath}
\begin{array}{ll}
41)\frac {1}{3}e^x-\frac {1}{9}\ln\vert ...
...ac {x}{2})\cos(\frac {x}{2})+\frac {3x}{8}+C\\
\end{array}
\end{displaymath}

$\displaystyle 57)-\frac {1}{5}\sin(x)\cos^4(x)+\frac {1}{15}\cos^2(x)\sin(x)+\frac {2}{15}\sin(x)+C$

\begin{displaymath}
\begin{array}{lll}
58)\frac {1}{5}(\cos(x)+2\sin(x))e^(x)\...
...59)^3\sqrt{\frac {1}{10}\cos^{10}(3x)}+C\\
\end{array}
\end{displaymath}





Farkas Lóránt 2002-11-24